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INAIO Guide Stage 1 4Sequences and Recurrences

4.2 Differences and patterns

Use differences and ratios to recognise likely sequence rules, while checking what the pattern does and does not prove.

A list of values rarely comes with its formula. Looking at the changes between terms is a useful first move: a fixed first difference suggests a line; a fixed second difference suggests a quadratic; a fixed ratio suggests repeated multiplication. This is useful for pattern questions, tables of measurements, and deciding which model to try.

This is foundational to intermediate work. Review arithmetic and geometric sequences first. OpenStax's sequence lesson gives more practice writing a rule from terms.

A basic idea: make a second row

For 2,5,10,17,262,5,10,17,26, subtract each term from the next. The first differences are 3,5,7,93,5,7,9. They are not constant, so an arithmetic rule does not fit. Subtract again: the second differences are 2,2,22,2,2. A quadratic is a good candidate. Here an=n2+1a_n=n^2+1 gives all five listed terms when nn starts at 11.

Rows show sequence terms 2, 5, 10, 17, 26; first differences 3, 5, 7, 9; and second differences 2, 2, 2.Rows show sequence terms 2, 5, 10, 17, 26; first differences 3, 5, 7, 9; and second differences 2, 2, 2.
Constant second differences point towards a quadratic rule.

A quick tour of pattern clues

What stays constant? Likely simple rule Example
First difference Linear in nn 4,7,10,134,7,10,13
Second difference Quadratic in nn 2,5,10,172,5,10,17
Ratio of consecutive nonzero terms Geometric or exponential 4,6,9,13.54,6,9,13.5

These tests assume equally spaced positions: term 1, term 2, term 3, and so on. For an=An2+Bn+Ca_n=An^2+Bn+C, the second difference is 2A2A when the index rises by 11. So a second difference of 22 suggests A=1A=1; the first two terms then determine BB and CC.

For a ratio, divide each term by its predecessor. The sequence 4,6,9,13.54,6,9,13.5 has ratio 1.51.5 each time, although its differences are 2,3,4.52,3,4.5. A changing difference can still come from a very simple multiplier.

A finite list never proves a unique continuation. Many formulas can match its first five terms and differ later. Use the story behind the data, a stated rule, or extra terms to choose a model. Differences and ratios are clues, not a substitute for checking the proposed rule.

Application 1: square tiles with one extra

A pattern uses 2,5,10,17,262,5,10,17,26 tiles in designs 11 through 55. Each design is an nn by nn square plus one extra tile. Predict design 66 and explain why.

  1. Read the structure. Design nn has n2n^2 square tiles and 11 extra, so an=n2+1a_n=n^2+1.
  2. Check the list. a1=2a_1=2, a2=5a_2=5, and a5=26a_5=26 agree.
  3. Predict. a6=62+1=37a_6=6^2+1=37. The differences predict the same result: the next first difference is 1111, and 26+11=3726+11=37.

The picture of the design supplies a reason for the formula; the table alone would not.

Application 2: a repeated multiplier

A lab model records 16,24,36,5416,24,36,54 units at four equally spaced observations. If the same multiplicative rule continues, what is the next model value?

  1. Compare ratios. 24/16=36/24=54/36=3/224/16=36/24=54/36=3/2. The differences, 8,12,188,12,18, are not constant.
  2. Write the candidate rule. With observation 1 as the start, an=16(3/2)n−1a_n=16(3/2)^{n-1}.
  3. Predict and check. a5=54(3/2)=81a_5=54(3/2)=81. Substituting n=4n=4 gives 16(3/2)3=5416(3/2)^3=54, matching the last known value.

This prediction is conditional on the model continuing; observations could change for reasons the short table does not show.

Resources

SourceTitleWhy read it
OpenStaxSequences and their notationsPractise moving from listed terms to a rule.

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